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#include <algorithm> #include <vector> #include <list> #include <deque> #include <iostreamh> template <class Type> void print_elements( Type elem ) { cout elem " "; } void (*pfi)( int ) = print_elements; int main() { int ia[] = {29,23,20,22,17,15,26,51,19,12,35,40}; int ia2[] = {74,16,39,54,21,44,62,10,27,41,65,71}; vector< int, allocator > vec1( ia, ia +12 ), vec2( ia2, ia2+12 ); int ia_result[24]; vector<int,allocator> vec_result(vec1size()+vec2size()); sort( ia, ia +12 ); sort( ia2, ia2+12 ); // generates: // 10 12 15 16 17 19 20 21 22 23 26 27 29 35 // 39 40 41 44 51 54 62 65 71 74 merge( ia, ia+12, ia2, ia2+12, ia_result ); for_each( ia_result, ia_result+24, pfi ); cout "\n\n"; sort( vec1begin(), vec1end(), greater<int>() ); sort( vec2begin(), vec2end(), greater<int>() ); merge( vec1begin(), vec1end(), vec2begin(), vec2end(), vec_resultbegin(), greater<int>() ); // generates: // 74 71 65 62 54 51 44 41 40 39 35 29 27 26 23 22 // 21 20 19 17 16 15 12 10 for_each( vec_resultbegin(), vec_resultend(), pfi ); cout "\n\n"; } mismatch() template< class InputIterator1, class InputIterator2 > pair<InputIterator1, InputIterator2> mismatch( InputIterator1 first1, InputIterator1 last, InputIterator2 first2 ); template< class InputIterator1, class InputIterator2, class BinaryPredicate > pair<InputIterator1, InputIterator2> mismatch( InputIterator1 first1, InputIterator1 last, InputIterator2 first2, BinaryPredicate pred );

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Development Conditions: Visual Studio 2005/ 2008 /2010, . NET Version 2.0 or above, IIS (Microsoft Internet Information Services), C#. NET , or VB .

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mismatch() compares two sequences in parallel and identifies the first position in which the elements do not match A pair of iterators is returned identifying the first position in which the elements do not match If all the elements match, then an iterator to the

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last element of each container is returned For example, given the sequences meet and meat, the two iterators addressing the third element are returned By default, the equality operator is used for element comparison; the second version allows the user to specify an alternative comparison operation If the second sequence contains more elements than the first, those elements are ignored If the second sequence contains less elements than the first, the run-time behavior is undefined

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#include <algorithm> #include <list> #include <utility> #include <iostreamh> class equal_and_odd{ public: bool operator()( int ival1, int ival2 ) { // are the two values equal, and either // both zero, or both odd return ( ival1 == ival2 && ( ival1 == 0 || ival1%2 )); } }; int main() { int ia[] = { 0,1,1,2,3,5,8,13 }; int ia2[] = { 0,1,1,2,4,6,10 }; pair<int*,int*> pair_ia = mismatch( ia, ia+7, ia2 ); // generates: first mismatched pair: ia: 3 and ia2: 4 cout "first mismatched pair: ia: " *pair_iafirst " and ia2: " *pair_iasecond endl; list<int,allocator> ilist( ia, ia+7 ); list<int,allocator> ilist2( ia2, ia2+7 ); typedef list<int,allocator>::iterator iter; pair< iter,iter > pair_ilist = mismatch( ilistbegin(), ilistend(), ilist2begin(), equal_and_odd() ); // generates: // first mismatched pair either not equal or not odd: // ilist: 2 and ilist2: 2 cout "first mismatched pair either not equal " "or not odd: \n\tilist: " *pair_ilistfirst " and ilist2: " *pair_ilistsecond endl; } next_permutation() template< class BidirectionalIterator > bool next_permutation( BidirectionalIterator first, BidirectionalIterator last ); template< class BidirectionalIterator, class Compare > bool next_permutation( BidirectionalIterator first, BidirectionalIterator last, Compare comp );

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next_permutation() takes the permutation marked off by [first, last) and reorders it into its next permutation (see Section 125 for a discussion of how the previous permutation is determined) If no next permutation exists, it returns false; otherwise, it returns true The first version uses the less than operator of the underlying type for determining the next permutation; the second version orders the elements based on comp Successive invocations of next_permutation() generate the entire permutation set only if the original string is sorted For example, in the following program, if we failed to sort musil into ilmsu, we would not generate the full set of permutations

#include <algorithm> #include <vector> #include <iostreamh> void print_char( char elem ) { cout elem ; } void (*ppc)( char ) = print_char; /* generates: ilmsu ilmus ilsmu ilsum ilums ilusm imlsu imlus imslu imsul imuls imusl islmu islum ismlu ismul isulm isuml iulms iulsm iumls iumsl iuslm iusml limsu limus lismu lisum liums liusm lmisu lmius lmsiu lmsui lmuis lmusi lsimu lsium lsmiu lsmui lsuim lsumi luims luism lumis lumsi lusim lusmi milsu milus mislu misul miuls miusl mlisu mlius mlsiu mlsui mluis mlusi msilu msiul msliu mslui msuil msuli muils muisl mulis mulsi musil musli silmu silum simlu simul siulm siuml slimu slium slmiu slmui sluim slumi smilu smiul smliu smlui smuil smuli suilm suiml sulim sulmi sumil sumli uilms uilsm uimls uimsl uislm uisml ulims ulism ulmis ulmsi ulsim ulsmi umils umisl umlis umlsi umsil umsli usilm usiml uslim uslmi usmil usmli */ int main() { vector<char,allocator> vec(5); // the character sequence: musil vec[0] = 'm'; vec[1] = 'u'; vec[2] = 's'; vec[3] = 'i'; vec[4] = 'l'; int cnt = 2; sort( vecbegin(), vecend() ); for_each( vecbegin(), vecend(), ppc ); cout "\t"; // generate all the permutations of "musil" while( next_permutation( vecbegin(), vecend())) { for_each( vecbegin(), vecend(), ppc ); cout "\t"; if ( ! ( cnt++ % 8 )) { cout "\n"; cnt = 1; } } cout "\n\n"; return 0; } nth_element() template< class RandomAccessIterator > void

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